Or ax 1234h or 0ffh

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WebDoc-9MXMRS；本文是“资格或认证考试”中“教师资格考试”的实用应用文的论文参考范文或相关资料文档。正文共16,068字，word格式文档。内容摘要：填空，位偏移量）和（SP）提供，单项选择题，判断题(你认为正确的，请在题末的括号内打“√”，错的打“×，简答题，位机，如何响应一个可屏蔽 ... Webmov ax,dividendLow cwd; sign-extend dividend mov bx,divisor idiv bx (7.4.7 p8) What will be the contents of AX and DX after the following operation? mov dx,0 mov ax,222h mov cx,100h mul cx Ans.: DX = 0002h, AX = 2200h. (7.4.7 p9) What will be the contents of AX after the following operation? mov ax,63h mov bl,10h div bl Ans.: AX = 0306h.

微机原理课后习题解答 - 豆丁网

WebExample: MOV AL, 0FFh DAS RET ; AL = 0FFh (-1) ; AL = 99h, CF = 1. CZSOPA rrrrrr. Decrement. Algorithm: operand = operand - 1 Example: ... Example: MOV AX, 1234h PUSH AX POP DX ; DX = 1234h RET 8086 instructions. Page 41 of 53. CZSOPA unchanged. Push all general purpose registers AX, CX, DX, BX, SP, BP, SI, DI in the stack. Original value of SP … Web8. (5 points) Write a short sequence of instructions to store the contents of the CX register at theword memory location contained in CX. Thus if CX contains 1234h, the number 1234h will be stored at locations DS:1234h and DS:1235h in memory. mov bx,cx mov [bx],cx mov bx , cx mov [ bx ] , cx portland maine gastroenterologists

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WebAs far as the CPU is concerned, or eax, -1 depends on the previous value of the eax register, which lengthens the code's dependency chain and will significantly decrease performance … Web.data myByte BYTE 0FFh, 0 .code mov al,myByte ; AL = mov ah, [myByte+1] ; AH = AL = FFh AH = 00h .data var1 DWORD 10000h var2 DWORD 20000h .code ; ---EAX--- mov eax,var1 ; a.) add eax,var2 ; b.) add ax,0FFFFh ; c.) add eax,1 ; d.) sub ax,1 ; e.) a.) 00010000h b.) 00030000h c.) 0003FFFFh d.) 00040000h e.) 0004FFFFh Sets with similar terms http://service.scs.carleton.ca/sivarama/asm_book_web/Student_copies/ch6_arithmetic.pdf opticut 5.25 keygen

微型计算机技术与应用第3章 Pentium的指令系统 P123.ppt-原创力 …

WebStudy with Quizlet and memorize flashcards containing terms like 21. The following statement will assemble without errors: mov WORD PTR [eax], 1234h, 22. The following … Webin the al register to the bl register, given ax =1234h and 3. assembly language instructions. (Total, P, Q and R are one byte long variables and are positive numbers). Total =P-Q+R 4. Determine if the following instructions are legal or not. This problem has been solved! opticus prime berlinWebmov ax,7FFFh add ax,2 ; SF = 1 ; Carry flag example: mov al,0FFh add al,1 ; CF = 1, AL = 00 ; Overflow flag example: mov al,+127 add al,1 ; OF = 1 mov al,-128 sub al,1 ; OF = 1 exit main ENDP END main Programming Exercises 1. Indicate whether or not each of the following instructions is valid. a. add ax,bx b. add dx,bl opticut free online

"WebOct 17, 2009 · Some examples contain macros, so it is advisable to use Shift + F8 hot key to Step Over (to make macro code execute at maximum speed set step delay to zero), otherwise emulator will step through... " - Or ax 1234h or 0ffh

Or ax 1234h or 0ffh

WebDec 31, 2024 · This instruction does more or less the opposite of MOV AX, [BX]: It writes data to memory. This time, the data in the register BX is written to the memory specified by the registers DS and AX. Because on x86 systems the low byte of some data is stored in the first byte and the high byte is stored in the second byte, the value 1234h would be ... Web微机原理和接口技术习题答案解析第1章微机运算基础习题和思考题1. 请完成以下计算:17466d10101110.10101bae. a8h10101110101.01011b 1397.344d575.58h4bch010b bcd2.

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Webanswer bank (DX=FFFFh, AX=80C0h / shl ebx, 3 / shl ebx, 5) 18. What will be the hexadecimal values of DX and AX after the following instructions have executed? mov ax, 3456h mov dx, 12h mov bx, 10h div bx Choose one answer. a. DX=0006h, AX=2345h b. DX=1234h, AX=0056h c. DX=0056h, AX=1234h d. cannot be determined 19. WebIf AX-1234H and DX- 20FFH, list the sum and the contents of each flag register bit (C, S, and Z) after the ADD AX, DX instruction executes. 2. This problem has been solved!

Webif using BX, the operand is defaultly located in Data segment,then: PA= (DS)*10H+ (BX)+ (DI)/ (SI)+disp if using BP, the operand is defaultly located in stack segment,then: PA= (SS)*10H+ (BP)+ (DI)/ (SI)+disp 16 f Based Indexed Relative Addressing MOV [BX+DI+1234H], AH 88 ;assume (ds)=4000h, (bx)=0200h, (di)=0010h ;machine code:88A13412h A1 Webmov ax,00FFh inc ax ; AX = 0100h mov ax,00FFh inc al ; AX = 0000h Show the value of the destination operand after each of the following instructions executes: .data myByte BYTE …

WebFeb 4, 2024 · (2)将存储单元 3000h 和内容送至 4000h 单元。 (3)将累加器 aX 与寄存器 cx 中的内容对调. 答案：（1)mov aX， 1234H Mov ds, ax movAx, [3000H] mov [4000H], ax xchgax, cx 12.编程：将数据段中以 Bx 为偏移地址的连续单元的内容颠倒过来。 Web摘要 ds=091dh 孙德文微型计算机技术答案 ds=091dh 已知ds=091dh,ss=1e4ah,ax=1234h,bx=0024h,cx=5678h,bp=0024h,si 微型计算机技术第四版答案孙德文

WebFeb 23, 2024 · Types of addressing modes: Register mode – In this type of addressing mode both the operands are registers. Example: MOV AX, BX XOR AX, DX ADD AL, BL. … opticus nerveWebORG 100h LEA AX, m RET m DW 1234h END AX is set to: 0104h. LEA instruction takes 3 bytes, RET takes 1 byte, we start at 100h, so the address of 'm' is 104h. LES REG, memory Load memory double word into word register and ES. Algorithm: REG = first word; ES = second word; Example: ORG 100h LES AX, m RET m DW 1234h DW 5678h END AX is set … opticusyWebNov 21, 2024 · AX=FFFFh CF=1(result is not 0) SF=1 ZF=0 PF=1 OF=0 Question 2: a) Suppose that AX and BX both contains +ive numbers, and ADD AX, BX is executed , show that there is carry into the MSB but no carry out of the MSB if and only if, signed overflow occurs. Solution: As we know signed overflow occurs if and if: There is a carry into the … opticventures gmbhWebJZ JNC JP JA JGE JLE Hand assemble the following codes: MOV BX, AX MOV BX, 01234H MOV BX [BP] MOV [SI+5] BX MOV [BX+SI], AL MOV AH, XYZ; Assume that XYZ is located … opticus sankt goarshausenWebMOV AX, [BX] ; Suppose the register BX contains 4895H, then the contents ; 4895H are moved to AX ADD CX, {BX} Based addressing mode In this addressing mode, the offset … opticvisionWebMOV AX,BҮТE1 AX=1234H AX= d. ADD DL,BYTE DX=0122H DX= e. INC DX DX=FF12H DX= f. INC DL DX=FF23H DX= g. XCHG AL,AH AX=1234H AX= h. SUB CL,CH CX=3451H CX= Question For each of the following unrelated instructions, show the result in the destination operand. Indicate if the instruction is invalid. Assume BYTE1 is defined as DB 05. portland maine general assistanceWebThere are 8 different addressing modes in 8086 programming − Immediate addressing mode The addressing mode in which the data operand is a part of the instruction itself is known as immediate addressing mode. Example MOV CX, 4929 H, ADD AX, 2387 H, MOV AL, FFH Register addressing mode opticus vision